Spring Boot 集成 JPA 的步骤

本贴最后更新于 2444 天前,其中的信息可能已经东海扬尘

Spring Boot 集成 JPA 的步骤

配置依赖

compile group: 'org.springframework.boot', name: 'spring-boot-starter-data-jpa', version: '1.5.2.RELEASE'
compile group: 'mysql', name: 'mysql-connector-java', version: '5.1.41'

编写配置文件

1、JPA 的配置

@EnableJpaRepositories(basePackages = "com.liwei.dao")
@EntityScan(basePackages = "com.liwei.entity")
public class JpaConfig {
}

2、数据库连接的配置和其它配置

spring.datasource.username=root
spring.datasource.password=123456
spring.datasource.url=jdbc:mysql://localhost:3306/spring-boot-security?useUnicode=true&characterEncoding=UTF-8
spring.datasource.driver-class-name=com.mysql.jdbc.Driver
spring.jpa.database-platform=org.hibernate.dialect.MySQLDialect
spring.jpa.show-sql=true

spring.jpa.hibernate.ddl-auto=update

创建数据库的 SQL 语句:

CREATE DATABASE `spring-boot-security` DEFAULT CHARSET utf8 COLLATE utf8_general_ci;

编写 dao 层和 entity 的代码

public interface UserRepository extends JpaRepository<User, Long> {
    User findByUserName(String userName);
}
public interface UserRolesRepository extends JpaRepository<UserRole,Long> {

}
@Table(name = "t_user")
@Entity
public class User {

    private Long userId;
    private String userName;
    private String password;
    private String email;
    private int enabled;

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    @Column(name = "user_id")
    public Long getUserId() {
        return userId;
    }

    public void setUserId(Long userId) {
        this.userId = userId;
    }

    @Column(name = "user_name")
    public String getUserName() {
        return userName;
    }

    public void setUserName(String userName) {
        this.userName = userName;
    }

    public String getPassword() {
        return password;
    }

    public void setPassword(String password) {
        this.password = password;
    }

    public String getEmail() {
        return email;
    }

    public void setEmail(String email) {
        this.email = email;
    }

    public int getEnabled() {
        return enabled;
    }

    public void setEnabled(int enabled) {
        this.enabled = enabled;
    }

    public User() {
    }

    public User(Long userId, String userName, String password, String email, int enabled) {
        this.userId = userId;
        this.userName = userName;
        this.password = password;
        this.email = email;
        this.enabled = enabled;
    }

    @Override
    public String toString() {
        return "User{" +
                "userId=" + userId +
                ", userName='" + userName + '\'' +
                ", password='" + password + '\'' +
                ", email='" + email + '\'' +
                ", enabled=" + enabled +
                '}';
    }
}
@Table(name = "t_user_roles")
@Entity
public class UserRole {

    private Long userRoleId;

    private Long userId;

    private String role;

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    @Column(name = "user_role_id")
    public Long getUserRoleId() {
        return userRoleId;
    }

    public void setUserRoleId(Long userRoleId) {
        this.userRoleId = userRoleId;
    }

    @Column(name = "user_id")
    public Long getUserId() {
        return userId;
    }

    public void setUserId(Long userId) {
        this.userId = userId;
    }

    public String getRole() {
        return role;
    }

    public void setRole(String role) {
        this.role = role;
    }
}

为了便于测试,我们还编写了服务层的方法:

public interface IUserService {

    User findByUserName(String userName);
}
@Service
public class UserServiceImpl implements IUserService {

    @Autowired
    private UserRepository userRepository;

    @Override
    public User findByUserName(String userName) {
        return userRepository.findByUserName(userName);
    }
}

编写测试代码

testCompile group: 'org.springframework.boot', name: 'spring-boot-starter-test', version: '1.5.2.RELEASE'
@RunWith(SpringRunner.class)
@SpringBootTest(classes = SpringBootSecurityApplication.class)
public class IUserServiceTest {

    @Autowired
    private IUserService userService;
    @Autowired
    private UserRepository userRepository;

    @Test
    public void initData() throws Exception {
        User user = new User();
        user.setUserName("liwei");
        user.setPassword("123456");
        user.setEmail("121088825");
        user.setEnabled(1);
        User user1 = userRepository.save(user);
        System.out.println(user1);
    }

    @Test
    public void findByUserName() throws Exception {
        User user = userService.findByUserName("liwei");
        System.out.println(user);

    }

}
  • 技术

    到底什么才是技术呢?

    88 引用 • 179 回帖 • 4 关注

相关帖子

欢迎来到这里!

我们正在构建一个小众社区,大家在这里相互信任,以平等 • 自由 • 奔放的价值观进行分享交流。最终,希望大家能够找到与自己志同道合的伙伴,共同成长。

注册 关于
请输入回帖内容 ...